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0.0025x^2-2.47x+400=0
a = 0.0025; b = -2.47; c = +400;
Δ = b2-4ac
Δ = -2.472-4·0.0025·400
Δ = 2.1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.47)-\sqrt{2.1009}}{2*0.0025}=\frac{2.47-\sqrt{2.1009}}{0.005} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.47)+\sqrt{2.1009}}{2*0.0025}=\frac{2.47+\sqrt{2.1009}}{0.005} $
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